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1888 United States presidential election in Rhode Island

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1888 United States presidential election in Rhode Island
Flag of Rhode Island (1882-1897).svg
  1884
November 6, 1888
1892  
  Benjamin Harrison 1896.jpg StephenGroverCleveland.jpg
Nominee Benjamin Harrison Grover Cleveland
Party Republican Democratic
Home state Indiana New York
Running mate Levi P. Morton Allen G. Thurman
Electoral vote40
Popular vote21,96917,530
Percentage53.88%42.99%

Rhode Island Presidential Election Results 1888.svg
Rhode Island Presidential Election Municipality Results 1888.svg

President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Rhode Island took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Rhode Island voted for the Republican nominee, Benjamin Harrison, over the Democratic nominee, incumbent President Grover Cleveland. Harrison won the state by a margin of 10.89%.

Results

1888 United States presidential election in Rhode Island [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 21,96953.88%4100.00%
Democratic Grover Cleveland of New York (incumbent) Allen Granberry Thurman of Ohio 17,53042.99%00.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 1,2513.07%00.00%
Union Labor Alson Streeter of Illinois Charles E. Cunningham of Arkansas 180.04%00.00%
N/AOthersOthers70.02%00.00%
Total40,775100.00%4100.00%

See also

References

  1. "1888 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved December 23, 2013.


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