1880 United States presidential election in Rhode Island

←  1876 November 2, 1880 1884  →

Nominee James A. Garfield Winfield S. Hancock Party Republican Democratic Home state Ohio Pennsylvania Running mate Chester A. Arthur William H. English Electoral vote 4 0 Popular vote 18,195 10,779 Percentage 62.24% 36.87%

County Results Municipality Results Garfield   50–60%   60–70%   70–80%   80–90% Hancock   50–60%   60–70%

President before election Rutherford B. Hayes Republican Elected President James A. Garfield Republican

The 1880 United States presidential election in Rhode Island took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

• Results
• See also
• References

Rhode Island voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 25.37%.

With 62.24% of the popular vote, Rhode Island would be Garfield's fourth strongest victory in terms of percentage in the popular vote after Vermont, Nebraska and Minnesota. ^[1]

This was the last time until 1964 that a Democrat won the town of North Kingstown.

Results

See also

• United States presidential elections in Rhode Island

References

This Rhode Island elections-related article is a stub. You can help Wikipedia by adding missing information.

• v
• t
• e