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1868 United States presidential election in Oregon

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1868 United States presidential election in Oregon
Flag of Oregon.svg
  1864
November 3, 1868
1872  
  Hon. Horatio Seymour, N.Y - NARA - 528568 (cropped).jpg Ulysses S Grant by Brady c1870-restored (3x4 crop).jpg
Nominee Horatio Seymour Ulysses S. Grant
Party Democratic Republican
Home state New York Illinois
Running mate Francis Preston Blair Jr. Schuyler Colfax
Electoral vote30
Popular vote11,12510,961
Percentage50.37%49.63%

Oregon Presidential Election Results 1868.svg
County Results

President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Oregon took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Contents

Oregon voted for the Democratic nominee, Horatio Seymour over the Republican nominee, Ulysses S. Grant. Seymour won the state by a narrow margin of 0.74%.

As a result of his win, Seymour became the first Democratic presidential candidate to ever win Oregon. Another Democrat would not win Oregon again on a presidential level until Woodrow Wilson won the state in 1912. Democrats wouldn't again win a majority in Oregon until Franklin D. Roosevelt won the state in 1932.

This was the only time a Republican would win a presidential election without Oregon until 1988, 120 years later; every Republican since then has lost the state.

Results

1868 United States presidential election in Oregon [1]
PartyCandidateRunning matePopular voteElectoral vote
Count%Count%
Democratic Horatio Seymour of New York Francis Preston Blair Jr. of Missouri 11,12550.37%3100.00%
Republican Ulysses S. Grant of Illinois Schuyler Colfax of Indiana 10,96149.63%00.00%
Total22,086100.00%3100.00%

See also

References

  1. "1868 Presidential General Election Results - Oregon".


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