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1800 United States presidential election in Connecticut

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1800 United States presidential election in Connecticut
Flag of Connecticut.svg
  1796 October 31 – December 3, 1800 1804  
  Gilbert Stuart, John Adams, c. 1800-1815, NGA (3x4 cropped).jpg James Earl - General Charles Cotesworth Pinckney - Google Art Project (3x4 cropped b).jpg
Nominee John Adams Charles Cotesworth Pinckney
Party Federalist Federalist
Home state Massachusetts South Carolina
Electoral vote99
Percentage100.00%

President before election

John Adams
Federalist

Elected President

Thomas Jefferson
Democratic-Republican

The 1800 United States presidential election in Connecticut took place between October 31 and December 3, 1800, as part of the 1800 United States presidential election. The state legislature chose nine representatives, or electors, to the Electoral College, who voted for President and Vice President. [1]

Connecticut cast nine electoral votes for incumbent Federalist President and New England native John Adams. However, Adams would lose to Democratic-Republican candidate Thomas Jefferson nationally.

See also

References

  1. Congressional Quarterly's guide to US elections (2. ed.). Washington, D.C.: Congressional Quarterly. 1985. pp. 254–256. ISBN   9780871873392 . Retrieved July 3, 2023.


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